c^2+2c-35=0

Solution for c^2+2c-35=0 equation:

Simplifying
c2 + 2c + -35 = 0

Reorder the terms:
-35 + 2c + c2 = 0

Solving
-35 + 2c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-7 + -1c)(5 + -1c) = 0

Subproblem 1
Set the factor '(-7 + -1c)' equal to zero and attempt to solve:

Simplifying
-7 + -1c = 0

Solving
-7 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + -1c = 0 + 7

Combine like terms: -7 + 7 = 0
0 + -1c = 0 + 7
-1c = 0 + 7

Combine like terms: 0 + 7 = 7
-1c = 7

Divide each side by '-1'.
c = -7

Simplifying
c = -7
Subproblem 2
Set the factor '(5 + -1c)' equal to zero and attempt to solve:

Simplifying
5 + -1c = 0

Solving
5 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1c = 0 + -5
-1c = 0 + -5

Combine like terms: 0 + -5 = -5
-1c = -5

Divide each side by '-1'.
c = 5

Simplifying
c = 5
Solution
c = {-7, 5}